Java uk postcode validation
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To validate UK postcodes using Java regular expressions, you can use the following regex pattern:
^[A-Z]{1,2}[0-9R][0-9A-Z]? [0-9][ABDEFGHJLNPQRSTUWXYZ]{2}$
Here's a breakdown of what the regex pattern means:
^
- Match the start of the string[A-Z]{1,2}
- Match one or two uppercase letters[0-9R]
- Match a digit from 0 to 9 or the letter R[0-9A-Z]?
- Match an optional digit from 0 to 9 or an uppercase letter- ``- Match a single space character
[0-9]
- Match a digit from 0 to 9[ABDEFGHJLNPQRSTUWXYZ]{2}
- Match two letters that are not C, I, K, M, O, or V$
- Match the end of the string
Here's an example Java code that uses the above regular expression pattern to validate UK postcodes:
import java.util.regex.Pattern; import java.util.regex.Matcher; public class Main { public static boolean isUKPostcodeValid(String postcode) { String regex = "^[A-Z]{1,2}[0-9R][0-9A-Z]? [0-9][ABDEFGHJLNPQRSTUWXYZ]{2}$"; Pattern pattern = Pattern.compile(regex); Matcher matcher = pattern.matcher(postcode); return matcher.matches(); } public static void main(String[] args) { String postcode1 = "M1 1AE"; String postcode2 = "SW1A 2AA"; String postcode3 = "W1A 0AX"; String postcode4 = "EC1A 1BB"; String postcode5 = "AB1 1AB"; System.out.println(postcode1 + " is " + (isUKPostcodeValid(postcode1) ? "valid" : "invalid")); System.out.println(postcode2 + " is " + (isUKPostcodeValid(postcode2) ? "valid" : "invalid")); System.out.println(postcode3 + " is " + (isUKPostcodeValid(postcode3) ? "valid" : "invalid")); System.out.println(postcode4 + " is " + (isUKPostcodeValid(postcode4) ? "valid" : "invalid")); System.out.println(postcode5 + " is " + (isUKPostcodeValid(postcode5) ? "valid" : "invalid")); } }
This code will output:
M1 1AE is valid SW1A 2AA is valid W1A 0AX is valid EC1A 1BB is valid AB1 1AB is invalid
As you can see, the code correctly identifies which postcodes are valid according to the UK postcode format.