C# ConfigurationManager.OpenExeConfiguration - 加载了错误的文件？
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ConfigurationManager.OpenExeConfiguration - loads the wrong file?
提问by user9659
I have added multiple app.config (each with a differet name) files to a project, and set them to copy to the output directory on each build.
我在一个项目中添加了多个 app.config（每个都有不同的名称）文件，并将它们设置为在每次构建时复制到输出目录。
I try and access the contents of each file using this:
我尝试使用以下方法访问每个文件的内容：
System.Configuration.Configuration o = ConfigurationManager.OpenExeConfiguration(@"app1.config");
The code runs, but o.HasFile ends up False, and o.FilePath ends up "app1.config.config". If I change to code:
代码运行，但 o.HasFile 最终为 False，o.FilePath 最终为“app1.config.config”。如果我更改为代码：
System.Configuration.Configuration o = ConfigurationManager.OpenExeConfiguration(@"app1");
Then the code bombs with "An error occurred loading a configuration file: The parameter 'exePath' is invalid. Parameter name: exePath".
然后代码炸弹“加载配置文件时出错：参数'exePath'无效。参数名称：exePath”。
If I copy/paste the config file (so I end up with app1.config and app1.config.config) then the code runs fine, however, I posit this is not a good solution. My question is thus: how can I use ConfigurationManager.OpenExeConfiguration to load a config file corretly?
如果我复制/粘贴配置文件（所以我最终得到了 app1.config 和 app1.config.config），那么代码运行良好，但是，我认为这不是一个好的解决方案。我的问题是：如何使用 ConfigurationManager.OpenExeConfiguration 正确加载配置文件？
采纳答案by user9659
According to http://social.msdn.microsoft.com/Forums/en-US/winforms/thread/3943ec30-8be5-4f12-9667-3b812f711fc9the parameter is the location of an exe, and the method then looks for the config corresponding to that exe (I guess the parameter name of exePath makes sense now!).
根据 http://social.msdn.microsoft.com/Forums/en-US/winforms/thread/3943ec30-8be5-4f12-9667-3b812f711fc9参数是exe的位置，然后该方法查找配置对应于那个 exe（我猜 exePath 的参数名称现在有意义了！）。
回答by Francis Huang
To avoid this problem altogether, you can read in the config file as an XML file, for example:
为了完全避免这个问题，您可以将配置文件作为 XML 文件读取，例如：
using System.Xml;
using System.Xml.XPath;
XmlDocument doc = new XmlDocument();
doc.Load(System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location) + "\..\..\..\MyWebProject\web.config");
string value = doc.DocumentElement.SelectSingleNode("/configuration/appSettings/add[@key='MyKeyName']").Attributes["value"].Value;
回答by Ron Hagerman
using System.Reflection;
try
{
Uri UriAssemblyFolder = new Uri(System.IO.Path.GetDirectoryName(Assembly.GetExecutingAssembly().GetName().CodeBase));
string appPath = UriAssemblyFolder.LocalPath;
//Open the configuration file and retrieve
//the connectionStrings section.
Configuration config = ConfigurationManager.
OpenExeConfiguration(appPath + @"\" + exeConfigName);
ConnectionStringsSection section =
config.GetSection("connectionStrings")
as ConnectionStringsSection;
}
At least, this is the method I use when encrypting and decrypting the connectionStrings section for my console/GUI apps. exeConfigNameis the name of the executable including the .exe.
至少，这是我在为我的控制台/GUI 应用程序加密和解密 connectionStrings 部分时使用的方法。exeConfigName是可执行文件的名称，包括 .exe。
回答by user1697877
I can't remember where I found this solution but here is how I managed to load a specific exe configuration file:
我不记得我在哪里找到了这个解决方案，但这是我如何设法加载特定的 exe 配置文件：
ExeConfigurationFileMap map = new ExeConfigurationFileMap { ExeConfigFilename = "EXECONFIG_PATH" };
Configuration config = ConfigurationManager.OpenMappedExeConfiguration(map, ConfigurationUserLevel.None);
