C#：在您拥有 DirectoryInfo 的目录中创建一个新的 FileInfo
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C#: Creating a new FileInfo in a directory that you have the DirectoryInfo of
提问by Svish
I was just wondering when you have for example:
我只是想知道你什么时候有例如：
var dir = new DirectoryInfo(@"C:\Temp");
Is there an easier/clearer way to add a new file to that directory than this?
有没有比这更简单/更清晰的方法将新文件添加到该目录？
var file = new FileInfo(Path.Combine(dir.FullName, "file.ext"));
I'm thinking I can probably just make an extension method or something, but curious if something already exists that can't see here... I mean the DirectoryInfodoes have GetFiles()method for example.
我想我可能只是做一个扩展方法或其他东西，但很好奇是否已经存在一些在这里看不到的东西......我的意思是例如DirectoryInfo确实有GetFiles()方法。
采纳答案by Fredrik M?rk
What is it that you want to do? The title says "Creating a new file". A FileInfo object is not a file; it's an object holding information about a file (that may or may not exist). If you actually want to createthe file, there are a number of ways of doing so. One of the simplest ways would be this:
你想做什么？标题是“创建新文件”。FileInfo 对象不是文件；它是一个保存有关文件信息的对象（可能存在也可能不存在）。如果您确实想要创建文件，有多种方法可以这样做。最简单的方法之一是：
File.WriteAllText(Path.Combine(dir.FullName, "file.ext"), "some text");
If you want to create the file based on the FileInfoobject instead, you can use the following approach:
如果要改为基于FileInfo对象创建文件，可以使用以下方法：
var dir = new DirectoryInfo(@"C:\Temp");
var file = new FileInfo(Path.Combine(dir.FullName, "file.ext"));
if (!file.Exists) // you may not want to overwrite existing files
{
using (Stream stream = file.OpenWrite())
using (StreamWriter writer = new StreamWriter(stream))
{
writer.Write("some text");
}
}
As a side note: it is dir.FullName, not dir.FullPath.
作为旁注：它是dir.FullName，不是dir.FullPath。
回答by Bhaskar
Why don't you use:
你为什么不使用：
File.Create(@"C:\Temp\file.ext");
or
或者
var dir = new DirectoryInfo(@"C:\Temp");
File.Create(dir.FullName + "\file.ext");
回答by Jay Bazuzi
While there does exist Directorynfo.GetFiles()methods, they only return files that actually exist on disk. Path.Combineis about hypothetical paths.
虽然确实存在Directorynfo.GetFiles()方法，但它们只返回实际存在于磁盘上的文件。Path.Combine是关于假设路径。
Try these extension methods:
试试这些扩展方法：
public static FileInfo CombineWithFileName(this DirectoryInfo directoryInfo, string fileName)
{
return new FileInfo(Path.Combine(directoryInfo.Name, fileName));
}
public static DirectoryInfo CombineWithDirectoryName(this DirectoryInfo directoryInfo, string directoryName)
{
return new DirectoryInfo(Path.Combine(directoryInfo.Name, directoryName));
}
