Linux 所有文件夹和子文件夹的列表
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List of All Folders and Sub-folders
提问by Sandeep540
In Linux, I want to find out all Folder/Sub-folder name and redirect to text file
在 Linux 中，我想找出所有文件夹/子文件夹名称并重定向到文本文件
I tried ls -alR > list.txt, but it gives all files+folders
我试过了 ls -alR > list.txt，但它提供了所有文件+文件夹
采纳答案by Adem ?zta?
You can use find
您可以使用 find
find . -type d > output.txt
or tree
或者 tree
tree -d > output.txt
tree, If not installed on your system.
tree, 如果你的系统上没有安装。
If you are using ubuntu
如果您正在使用 ubuntu
sudo apt-get install tree
If you are using mac os.
如果您正在使用mac os.
brew install tree
回答by Amber
find . -type d > list.txt
Will list all directories and subdirectories under the current path. If you want to list all of the directories under a path other than the current one, change the .to that other path.
将列出当前路径下的所有目录和子目录。如果要列出当前路径以外的路径下的所有目录，请将 更改.为其他路径。
If you want to exclude certain directories, you can filter them out with a negative condition:
如果要排除某些目录，可以使用否定条件将它们过滤掉：
find . -type d ! -name "~snapshot" > list.txt
回答by Tony Delroy
As well as findlisted in other answers, better shells allow both recurvsive globs and filtering of glob matches, so in zshfor example...
除了find在其他答案中列出之外，更好的 shell 允许递归全局匹配和全局匹配过滤，zsh例如......
ls -lad **/*(/)
...lists all directories while keeping all the "-l" details that you want, which you'd otherwise need to recreate using something like...
...列出所有目录，同时保留您想要的所有“-l”详细信息，否则您需要使用类似...
find . -type d -exec ls -ld {} \;
(not quite as easy as the other answers suggest)
（不像其他答案所建议的那么容易）
The benefit of find is that it's more independent of the shell - more portable, even for system()calls from within a C/C++ program etc..
find 的好处是它更独立于 shell - 更便携，即使对于system()来自 C/C++ 程序等的调用也是如此。
