C# Gridview 中 TemplateField 中的复选框在回发时丢失
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Checkbox in TemplateField in Gridview loses checked on postback
提问by Jhorra
I have a gridview with a template field. In that template field is a checkbox. I have a submit button outside of the gridview to assign the records that were checked. On the postback no checkboxes register as being checked. Here is my Code:
我有一个带有模板字段的 gridview。在该模板字段中是一个复选框。我在 gridview 之外有一个提交按钮来分配已检查的记录。在回发时，没有复选框注册为被选中。这是我的代码：
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:CheckBox ID="cb" Checked="false" runat="server" />
<asp:Label ID="lblCFID" runat="server" Visible="false" Text='<%# Eval("ID") %>' />
</ItemTemplate>
</asp:TemplateField>
<asp:BoundField HeaderStyle-HorizontalAlign="Center" DataField="Name" HeaderText="Name" />
<asp:BoundField HeaderStyle-HorizontalAlign="Center" DataField="DOB" HeaderText="Date of Birth" />
<asp:BoundField HeaderStyle-HorizontalAlign="Center" HeaderText="Gender" DataField="Gender" />
<asp:BoundField HeaderStyle-HorizontalAlign="Center" HeaderText="Status" DataField="Status" />
<asp:BoundField HeaderStyle-HorizontalAlign="Center" HeaderText="Plan Name" DataField="PlanName" />
<asp:BoundField HeaderStyle-HorizontalAlign="Center" HeaderText="Type" DataField="ControlType" />
<asp:BoundField HeaderStyle-HorizontalAlign="Center" HeaderText="Date of Service" dataformatstring="{0:MMMM d, yyyy}" htmlencode="false" DataField="DateofService" />
</Columns>
protected void AssignRecords(object sender, EventArgs e)
{
int Rows = gvASH.Rows.Count;
for (int i = 0; i < Rows; i++)
{
//CheckBoxField cb = ((CheckBoxField)gvASH.Rows[i].Cells[1]).;
CheckBox cb = (CheckBox)gvASH.Rows[i].Cells[0].FindControl("cb");
Label lblID = (Label)gvASH.Rows[i].Cells[0].FindControl("lblCFID");
if (cb.Checked == true)
{
string ID = lblID.Text;
//Assign Code
}
}
}
I have a breakpoint set on the string ID = lblID.Text; but it never finds any that are checked.
我在字符串 ID = lblID.Text; 上设置了一个断点；但它从来没有找到任何被检查的。
采纳答案by Muhammad Akhtar
I think what you are missing is, when you click on the button and your page is postback, you rebinding to gridview, you need to bind in this condition like
我认为您缺少的是，当您单击按钮并且您的页面回发时，您重新绑定到 gridview，您需要在这种情况下进行绑定，例如
if (!Page.IsPostBack)
{
GridView1.DataSourceID = "yourDatasourceID";
GridView1.DataBind();
}
回答by Rich Wilson
On a postback, the contents of the GridView are re-created from the postback Viewstate data between page_init and page_load. Perhaps try examining your Gridview in page_load to see what's there.
在回发时，GridView 的内容是从 page_init 和 page_load 之间的回发 Viewstate 数据重新创建的。也许尝试在 page_load 中检查您的 Gridview 以查看那里有什么。
回答by Himanshu
set the autopostback attribute of Checkbox
设置 Checkbox 的 autopostback 属性
AutoPostBack="true"
