Linux 如何杀死僵尸进程
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How to kill zombie process
提问by MOHAMED
I launched my program in the foreground (a daemon program), and then I killed it with kill -9
, but I get a zombie remaining and I m not able to kill it with kill -9
. How to kill a zombie process?
我在前台启动了我的程序(一个守护程序),然后我用 杀死了它kill -9
,但是我留下了一个僵尸,我无法用kill -9
. 如何杀死僵尸进程?
If the zombie is a dead process (already killed), how I remove it from the output of ps aux
?
如果僵尸进程是死进程(已被杀死),我如何将其从ps aux
?
root@OpenWrt:~# anyprogramd &
root@OpenWrt:~# ps aux | grep anyprogram
1163 root 2552 S anyprogramd
1167 root 2552 S anyprogramd
1169 root 2552 S anyprogramd
1170 root 2552 S anyprogramd
10101 root 944 S grep anyprogram
root@OpenWrt:~# pidof anyprogramd
1170 1169 1167 1163
root@OpenWrt:~# kill -9 1170 1169 1167 1163
root@OpenWrt:~# ps aux |grep anyprogram
1163 root 0 Z [anyprogramd]
root@OpenWrt:~# kill -9 1163
root@OpenWrt:~# ps aux |grep anyprogram
1163 root 0 Z [anyprogramd]
采纳答案by William Pursell
A zombie is already dead, so you cannot kill it. To clean up a zombie, it must be waited on by its parent, so killing the parent should work to eliminate the zombie. (After the parent dies, the zombie will be inherited by pid 1, which will wait on it and clear its entry in the process table.) If your daemon is spawning children that become zombies, you have a bug. Your daemon should notice when its children die and wait
on them to determine their exit status.
僵尸已经死了,所以你不能杀死它。要清理僵尸,它必须由其父级等待,因此杀死父级应该可以消除僵尸。(在父进程死后,僵尸进程将被 pid 1 继承,它会等待它并清除它在进程表中的条目。)如果你的守护进程正在产生变成僵尸的子进程,那么你就有了一个错误。你的守护进程应该注意到它的子进程何时死亡并wait
在它们上面确定它们的退出状态。
An example of how you might send a signal to every process that is the parent of a zombie (note that this is extremely crude and might kill processes that you do not intend. I do not recommend using this sort of sledge hammer):
一个如何向作为僵尸父进程的每个进程发送信号的示例(请注意,这非常粗糙,可能会杀死您不想要的进程。我不建议使用这种大锤):
# Don't do this. Incredibly risky sledge hammer!
kill $(ps -A -ostat,ppid | awk '/[zZ]/ && !a[]++ {print }')
回答by Mohammad Rafiee
I tried:
我试过:
ps aux | grep -w Z # returns the zombies pid
ps o ppid {returned pid from previous command} # returns the parent
kill -1 {the parent id from previous command}
this will work :)
这将工作:)
回答by krishna murti
You can clean up a zombie process by killing its parent process with the following command:
您可以通过使用以下命令杀死其父进程来清理僵尸进程:
kill -HUP $(ps -A -ostat,ppid | grep -e '[zZ]'| awk '{ print }')
回答by Jeoffrey
I tried
我试过
kill -9 $(ps -A -ostat,ppid | grep -e '[zZ]'| awk '{ print }')
and it works for me.
它对我有用。
回答by Sergio
Found it at http://www.linuxquestions.org/questions/suse-novell-60/howto-kill-defunct-processes-574612/
在http://www.linuxquestions.org/questions/suse-novell-60/howto-kill-defunct-processes-574612/找到它
2) Here a great tip from another user (Thxs Bill Dandreta): Sometimes
2) 这是来自另一个用户的一个很好的提示 (Thxs Bill Dandreta):有时
kill -9 <pid>
will not kill a process. Run
不会杀死进程。跑
ps -xal
the 4th field is the parent process, kill all of a zombie's parents and the zombie dies!
第四个字段是父进程,杀死所有僵尸的父母,僵尸就死了!
Example
例子
4 0 18581 31706 17 0 2664 1236 wait S ? 0:00 sh -c /usr/bin/gcc -fomit-frame-pointer -O -mfpmat
4 0 18582 18581 17 0 2064 828 wait S ? 0:00 /usr/i686-pc-linux-gnu/gcc-bin/3.3.6/gcc -fomit-fr
4 0 18583 18582 21 0 6684 3100 - R ? 0:00 /usr/lib/gcc-lib/i686-pc-linux-gnu/3.3.6/cc1 -quie
18581
, 18582
, 18583
are zombies -
18581
, 18582
,18583
是僵尸——
kill -9 18581 18582 18583
has no effect.
没有效果。
kill -9 31706
removes the zombies.
移除僵尸。