在 Listbox.ItemTemplate (WPF C#) 中查找控件
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Find control inside Listbox.ItemTemplate (WPF C#)
提问by
I have some problems finding the right TextBlock
control inside a StackPanel
.
My markup:
我TextBlock
在StackPanel
. 我的标记:
<ListBox Name="lstTimeline" ItemContainerStyle="{StaticResource TwItemStyle}"
MouseDoubleClick="lstTimeline_MouseDoubleClick">
<ListBox.ItemTemplate>
<DataTemplate>
<DockPanel MaxWidth="{Binding ElementName=lstTimeline, Path=ActualWidth}">
<Border Margin="10" DockPanel.Dock="Left" BorderBrush="White"
BorderThickness="1" Height="48" Width="48" HorizontalAlignment="Center">
<Image Source="{Binding ThumbNail, IsAsync=True}" Height="48" Width="48" />
</Border>
<StackPanel Name="stkPanel" Margin="10" DockPanel.Dock="Right">
<TextBlock Text="{Binding UserName}" FontWeight="Bold" FontSize="18" />
<TextBlock Text="{Binding Text}" Margin="0,4,0,0" FontSize="14"
Foreground="#c6de96" TextWrapping="WrapWithOverflow" />
<TextBlock Text="{Binding ApproximateTime}" FontSize="14"
FontFamily="Georgia" FontStyle="Italic" Foreground="#BBB" />
<TextBlock Text="{Binding ScreenName}" Name="lblScreenName" FontSize="14"
FontFamily="Georgia" FontStyle="Italic" Foreground="#BBB"
Loaded="lblScreenName_Loaded" />
</StackPanel>
</DockPanel>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
My double click code:
我的双击代码:
private void lstTimeline_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
ListBoxItem lbi = (lstTimeline.SelectedItem as ListBoxItem);
StackPanel item = lbi.FindName("stkPanel") as StackPanel;
if (item != null)
MessageBox.Show("StackPanel null");
TextBlock textBox = item.FindName("lblScreenName") as TextBlock;
if (textBox != null)
MessageBox.Show("TextBlock null");
MessageBox.Show(textBox.Text);
}
But the StackPanel
is null. How do find the right TextBlock
in SelectedItem
?
但StackPanel
为空。如何在 中找到合适TextBlock
的SelectedItem
?
Thanks for your help.
谢谢你的帮助。
回答by David Hay
There's a specific function to use when you're looking for something whose name is defined in a template. Try it like this:
当您查找名称在模板中定义的内容时,可以使用特定的函数。像这样尝试:
private void lstTimeline_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
ListBoxItem lbi = (lstTimeline.SelectedItem as ListBoxItem);
StackPanel item = Template.FindName("stkPanel",lbi) as StackPanel;
if (item != null)
MessageBox.Show("StackPanel null");
TextBlock textBox = Template.FindName("lblScreenName",item) as TextBlock;
if (textBox != null)
MessageBox.Show("TextBlock null");
MessageBox.Show(textBox.Text);
}
回答by David Hay
Linq to xml with a get and set model.
使用获取和设置模型的 Linq to xml。
var item = ...
lstTimeline.SelectedIndex = -1;
lstTimeline.ItemsSource = item;
回答by Hari
ListBoxItem myListBoxItem = (ListBoxItem)(lstUniqueIds.ItemContainerGenerator.ContainerFromIndex(lstUniqueIds.SelectedIndex));
ContentPresenter myContentPresenter = FindVisualChild<ContentPresenter>(myListBoxItem);
DataTemplate myDataTemplate = myContentPresenter.ContentTemplate;
CheckBox target = (CheckBox)myDataTemplate.FindName("chkUniqueId", myContentPresenter);
if (target.IsChecked)
{
target.IsChecked = false;
}
else
{
target.IsChecked = true;
}
Function FindVisualChild
can be found on the MSDN page FrameworkTemplate.FindName Method:
函数FindVisualChild
可以在 MSDN 页面FrameworkTemplate.FindName 方法中找到:
private childItem FindVisualChild<childItem>(DependencyObject obj)
where childItem : DependencyObject
{
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(obj); i++)
{
DependencyObject child = VisualTreeHelper.GetChild(obj, i);
if (child != null && child is childItem)
return (childItem)child;
else
{
childItem childOfChild = FindVisualChild<childItem>(child);
if (childOfChild != null)
return childOfChild;
}
}
return null;
}