Linux 在 unix 上查找人类可读的文件
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Finding human-readable files on unix
提问by Yi?it
I'd like to find human-readable files on my linux machine without a file extension constraint. Those files should be of human sensing files like text, configuration, html, source-code etc. files. Could you suggest a way to filter and locate.
我想在没有文件扩展名限制的情况下在我的 linux 机器上找到人类可读的文件。这些文件应该是人类感知文件，如文本、配置、html、源代码等文件。你能提出一种过滤和定位的方法吗？
采纳答案by peteches
find and file are your friends here:
find 和 file 是你的朋友在这里：
find /dir/to/search -type f -exec sh -c 'file -b {} | grep text &>/dev/null' \; -print
this will find any files ( NOTE: it will not find symlinks directories sockets etc only regular files ) in /dir/to/search and run sh -c 'file -b {} | grep text &>/dev/null' \; which looks at the type of file and looks for text in the description. if this returns true ( ie text is in the line) then it prints the filename.
这将在 /dir/to/search 中找到任何文件（注意：它不会找到符号链接目录套接字等仅常规文件）并运行 sh -c 'file -b {} | grep text &>/dev/null' \; 它查看文件类型并在描述中查找文本。如果返回 true（即文本在行中），则它会打印文件名。
NOTE: using the -b flag to filemeans that the filename is not printed and therefore cannot create any issues with the grep. eg without the -b flag the binary file gettext would erroneously be detected as a textfile.
注意：对文件使用 -b 标志意味着不会打印文件名，因此不会对 grep 产生任何问题。例如，如果没有 -b 标志，二进制文件 gettext 将被错误地检测为文本文件。
eg
例如
root@osdevel-pete# find /bin -exec sh -c 'file -b {} | grep text &>/dev/null' \; -print
/bin/gunzip
/bin/svnshell.sh
/bin/unicode_stop
/bin/unicode_start
/bin/zcat
/bin/redhat_lsb_init
root@osdevel-pete# find /bin -type f -name *text*
/bin/gettext
EDIT:
编辑：
If you want to look in compressed files use the --uncompress flag to file. for more info and flags to file see man file
如果要查看压缩文件，请使用 --uncompress 标志来归档。有关要归档的更多信息和标志，请参阅man 文件
回答by Blam
How about
怎么样
find /dir/to/search -type f | xargs file | grep text
find /dir/to/search -type f | xargs file | grep text
findwill give you a list of files.
find会给你一个文件列表。
xargs filewill run the filecommand on each of the lines from the piped input.
xargs file将file在管道输入的每一行上运行命令。
回答by because_im_batman
Just wanted to share that this should work fine too.
只是想分享一下，这也应该可以正常工作。
file_info=`file "$file_name"` # first reading the file info string which should have the words "ASCII" or "Unicode" if its a readable file
if grep -q -i -e "ASCII" -e "Unicode"<<< "$file_info"; then
echo "file is readable"
fi
