Linux 使用 awk 替换正则表达式模式
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Substitute a regex pattern using awk
提问by Ajay Nair
I am trying to write a regex expression to replace one or more '+' symbols present in a file with a space. I tried the following:
我正在尝试编写一个正则表达式来用空格替换文件中存在的一个或多个“+”符号。我尝试了以下方法：
echo This++++this+++is+not++done | awk '{ sub(/\++/, " "); print }'
This this+++is+not++done
Expected:
预期的：
This this is not done
Any ideas why this did not work?
任何想法为什么这不起作用？
采纳答案by Guru
Use gsubwhich does global substitution:
使用gsubwhich 进行全局替换：
echo This++++this+++is+not++done | awk '{gsub(/\++/," ");}1'
subfunction replaces only 1st match, to replace all matches use gsub.
sub函数仅替换第一个匹配项，要替换所有匹配项，请使用gsub.
回答by alex
You could use sedtoo.
你也可以用sed。
echo This++++this+++is+not++done | sed -e 's/+\{1,\}/ /g'
This matches one or more +and replaces it with a space.
这匹配一个或多个+并用空格替换它。
回答by radical7
Or the trcommand:
或者tr命令：
echo This++++this+++is+not++done | tr -s '+' ' '
回答by Mirage
Try this
尝试这个
echo "This++++this+++is+not++done" | sed -re 's/(\+)+/ /g'
echo "This++++this+++is+not++done" | sed -re 's/(\+)+/ /g'
回答by Ed Morton
The idiomatic awk solution would be just to translate the input field separator to the output separator:
惯用的 awk 解决方案只是将输入字段分隔符转换为输出分隔符：
$ echo This++++this+++is+not++done | awk -F'++' '{=}1'
This this is not done
回答by dsri
echo "This++++this+++is+not++done" | sed 's/++*/ /g'
回答by mathiasrw
If you have access to node on your computer you can do it by installing rexreplace
如果您可以访问计算机上的节点，则可以通过安装 rexreplace 来实现
npm install -g regreplace
and then run
然后运行
rexreplace '\++' ' ' myfile.txt
Of if you have more files in a dir datayou can do
如果你在一个目录中有更多的文件，data你可以做
rexreplace '\++' ' ' data/*.txt
