Linux 如何 grep 精确的文字字符串（无正则表达式）
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How to grep exact literal string (no regex)
提问by Nathan J.B.
Is there a way to grep(or use another command) to find exact strings, using NO regex?
有没有办法grep（或使用另一个命令）不使用正则表达式来查找确切的字符串？
For example, if I want to search for (literally):
例如，如果我想搜索（字面意思）：
/some/file"that/has'lots\of"invalid"chars/and.triggers$(#2)[*~.old][3].html
I don't want to go through and escape every single "escapable". Essentially, I want to pass it through, like I would with echo:
我不想经历和逃避每一个“逃避”。本质上，我想通过它，就像我一样echo：
$ echo "/some/file\"that/has'lots\of\"invalid\"chars/and.triggers$(#2)[*~.old][3].html"
/some/file"that/has'lots\of"invalid"chars/and.triggers$(#2)[*~.old][3].html
采纳答案by pldoverflow
Use fgrep, it's the same as grep -F(matches a fixed string).
使用fgrep，它与grep -F（匹配固定字符串）相同。
回答by Rubens
Well, you can put the information you want to match, each in a line, and then use grep:
好吧，你可以把你想要匹配的信息，每一个都放在一行，然后使用grep：
grep -F -f patterns.txt file.txt
Notice the usage of the flag -F, which causes grepto consider each line of the file patterns.txtas a fixed-stringto be searched in file.txt.
注意标志的用法-F，它导致grep将文件patterns.txt 的每一行视为fixed-string要在file.txt 中搜索的a 。
