Linux 从 grep 输出中删除字符
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Removing characters from grep output
提问by Sam
I've been whittling down my grep output (which comes down to a listing of numbers that I intend to associate with other fields.) My problem is that numbers above 999 have commas in them, and I'm wondering how to print the output with out the commas.
我一直在缩减我的 grep 输出（归结为我打算与其他字段关联的数字列表。）我的问题是 999 以上的数字中有逗号，我想知道如何打印输出没有逗号。
so instead of the output being:
所以而不是输出是：
1,200,300
it would just be:
它只是：
1200300
Any suggestions for an additional pipe command that I could add?
关于我可以添加的额外管道命令的任何建议？
Thanks
谢谢
采纳答案by Akhil Thayyil
Try this
尝试这个
< your command > | tr -d ','
tr will remove all commas
tr 将删除所有逗号
回答by John3136
< your command > | sed -e 's/,//g'
This will replace all commas with "nothing" without changing anything else.
这将用“无”替换所有逗号而不更改任何其他内容。
回答by Vijay
instead of grep use a single awk command like below
而不是 grep 使用单个 awk 命令，如下所示
awk '/your pattern/{gsub(",","");print}' your_file
