Linux 使用 *nix 中的 column 命令格式化列表
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Formatting lists with the column command in *nix
提问by Doug Powers
I'm trying to format a list of entries in bash, and am using the columncommand. However, the -toption defaults to using any whitespace as a delimiter, which does not work for the data I have (it contains spaces and tabs). I can't figure out how to get the -sflag to specify a newline character as the sole column delimiter.
我正在尝试格式化 bash 中的条目列表，并且正在使用该column命令。但是，该-t选项默认使用任何空格作为分隔符，这不适用于我拥有的数据（它包含空格和制表符）。我无法弄清楚如何获取-s标志以将换行符指定为唯一的列分隔符。
采纳答案by ruakh
In theory, to specify a newline, you can use the $'...'notation, which is just like '...'except that it supports C-style escape-sequences:
理论上，要指定换行符，您可以使用$'...'表示法，'...'除了它支持 C 风格的转义序列之外，这就像：
column -t -s $'\n' list-of-entries.txt
However, I don't really understand the purpose of this. A newline is the row delimiter, so a column-delimiter of $'\n'is equivalent to not having any column-delimiter at all:
但是，我真的不明白这样做的目的。换行符是行分隔符，因此列分隔符 of$'\n'相当于根本没有任何列分隔符：
column -t -s '' list-of-entries.txt
which means that the input will be treated as having only one column; so it's equivalent to not using columnat all:
这意味着输入将被视为只有一列；所以它相当于根本不使用column：
cat list-of-entries.txt
It seems like you actually don'twant to use the -tflag, because the purpose of the -tflag is to ensure that each line of input becomes one line of output, and it doesn't sound like that's what you want. I'm guessing you want this:
好像你其实不希望使用-t标志，因为目的-t标志，以确保输入的每一行变为一行输出，它听起来不像这就是你想要的。我猜你想要这个：
column list-of-entries.txt
which will treat each line of list-of-entries.txtas a value to be put in one cell of the table that columnoutputs.
它将把每一行list-of-entries.txt作为一个值放入column输出表的一个单元格中。
回答by toobsco42
This works to output a pretty print version of a tab delimited file
这可以输出制表符分隔文件的漂亮打印版本
column -t -s $'\t' list-of-entries.txt
