C# 使用 LINQ 在一行代码中将 string[] 转换为 int[]

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时间:2020-08-06 14:49:54  来源:igfitidea点击:

Convert string[] to int[] in one line of code using LINQ

c#.netlinqextension-methods

提问by abatishchev

I have an array of integers in string form:

我有一个字符串形式的整数数组:

var arr = new string[] { "1", "2", "3", "4" };

I need to an array of 'real' integers to push it further:

我需要一个“真实”整数数组来进一步推动它:

void Foo(int[] arr) { .. }

I tried to cast int and it of course failed:

我试图转换 int 并且它当然失败了:

Foo(arr.Cast<int>.ToArray());

I can do next:

接下来我可以这样做:

var list = new List<int>(arr.Length);
arr.ForEach(i => list.Add(Int32.Parse(i))); // maybe Convert.ToInt32() is better?
Foo(list.ToArray());

or

或者

var list = new List<int>(arr.Length);
arr.ForEach(i =>
{
   int j;
   if (Int32.TryParse(i, out j)) // TryParse is faster, yeah
   {
      list.Add(j);
   }
 }
 Foo(list.ToArray());

but both looks ugly.

但两者都看起来很丑。

Is there any other ways to complete the task?

有没有其他方法可以完成任务?

采纳答案by Ahmad Mageed

Given an array you can use the Array.ConvertAllmethod:

给定一个数组,您可以使用该Array.ConvertAll方法

int[] myInts = Array.ConvertAll(arr, s => int.Parse(s));

Thanks to Marc Gravell for pointing out that the lambda can be omitted, yielding a shorter version shown below:

感谢 Marc Gravell 指出可以省略 lambda,从而生成如下所示的较短版本:

int[] myInts = Array.ConvertAll(arr, int.Parse);

A LINQ solution is similar, except you would need the extra ToArraycall to get an array:

LINQ 解决方案是类似的,除了您需要额外的ToArray调用来获取数组:

int[] myInts = arr.Select(int.Parse).ToArray();

回答by Simon Fox

EDIT: to convert to array

编辑:转换为数组

int[] asIntegers = arr.Select(s => int.Parse(s)).ToArray();

This should do the trick:

这应该可以解决问题:

var asIntegers = arr.Select(s => int.Parse(s));

回答by sepp2k

var list = arr.Select(i => Int32.Parse(i));

回答by Rob

var asIntegers = arr.Select(s => int.Parse(s)).ToArray(); 

Have to make sure you are not getting an IEnumerable<int>as a return

必须确保你没有得到IEnumerable<int>回报

回答by A.Dara

you can simply cast a string array to int array by:

您可以通过以下方式简单地将字符串数组转换为 int 数组:

var converted = arr.Select(int.Parse)

回答by Slai

To avoid exceptions with .Parse, here are some .TryParsealternatives.

为避免 出现异常.Parse,这里有一些.TryParse替代方法。

To use only the elements that can be parsed:

仅使用可以解析的元素:

string[] arr = { null, " ", " 1 ", " 002 ", "3.0" };
int i = 0; 
var a = (from s in arr where int.TryParse(s, out i) select i).ToArray();  // a = { 1, 2 }

or

或者

var a = arr.SelectMany(s => int.TryParse(s, out i) ? new[] { i } : new int[0]).ToArray();


Alternatives using 0for the elements that can't be parsed:

0用于无法解析的元素的替代方案:

int i; 
var a = Array.ConvertAll(arr, s => int.TryParse(s, out i) ? i : 0); //a = { 0, 0, 1, 2, 0 }

or

或者

var a = arr.Select((s, i) => int.TryParse(s, out i) ? i : 0).ToArray();

C# 7.0:

C# 7.0

var a = Array.ConvertAll(arr, s => int.TryParse(s, out var i) ? i : 0);