Linux Bash 将 awk 的输出捕获到数组中
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Bash capturing output of awk into array
提问by Paul
I am stuck on a little problem. I have a command which pipes output to awk but I want to capture the output of to an array one by one.
我被一个小问题困住了。我有一个命令将输出通过管道传输到 awk，但我想将输出一一捕获到数组中。
My example:
我的例子：
myarr=$(ps -u kdride | awk '{ print }')
But that capture all my output into one giant string separated by commas:
但这将我的所有输出捕获到一个用逗号分隔的巨大字符串中：
output: PID 3856 5339 6483 10448 15313 15314 15315 15316 22348 29589 29593 32657 1
I also tried the following:
我还尝试了以下方法：
IFS=","
myarr=$(ps -u kdride | awk '{ print "," }')
But the output is: PID, 3856, 5339, 6483, 10448, 15293, 15294, 15295, 15296, 22348, 29589, 29593, 32657,
1
I want to be able to capture each individual pid into its own array element. Setting IFS = '\n'does not do anything and retains my original output. What change do I need to do to make this work?
我希望能够将每个单独的 pid 捕获到它自己的数组元素中。设置IFS = '\n'不做任何事情并保留我的原始输出。我需要做哪些改变才能使这项工作发挥作用？
采纳答案by kamituel
Add additional parentheses, like this:
添加额外的括号，如下所示：
myarr=($(ps -u kdride | awk '{ print }'))
# Now access elements of an array (change "1" to whatever you want)
echo ${myarr[1]}
# Or loop through every element in the array
for i in "${myarr[@]}"
do
:
echo $i
done
See also bash— Arrays.
另请参阅bash- 数组。
回答by jarno
Use Bash's builtin mapfile(or its synonym readarray)
使用 Bash 的内置映射文件（或其同义词readarray）
mapfile -t -s 1 myarr < <(ps -u myusername | awk '{print }')
At least in GNU/Linux you can format output of ps, so no need for awkand -s 1
至少在 GNU/Linux 中你可以格式化输出ps，所以不需要awk和-s 1
mapfile -t myarr < <(ps -u myusername -o pid=)
