linux bash脚本获取用户输入并存储在数组中
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linux bash script get user input and store in a array
提问by Vignesh
I want to write a bash script that will get user input and store it in an array. Input: 1 4 6 9 11 17 22
我想编写一个 bash 脚本来获取用户输入并将其存储在一个数组中。输入：1 4 6 9 11 17 22
I want this to be saved as array.
我希望将其保存为数组。
采纳答案by anubhava
read it like this:
像这样阅读：
read -a arr
Test:
测试：
read -a arr <<< "1 4 6 9 11 17 22"
print # of elements in array:
打印数组中元素的数量：
echo ${#arr[@]}
OR loop through the above array
OR 循环遍历上述数组
for i in ${arr[@]}
do
echo $i # or do whatever with individual element of the array
done
回答by jh314
How about this:
这个怎么样：
while read line
do
my_array=("${my_array[@]}" $line)
done
printf -- 'data%s ' "${my_array[@]}"
Hit Ctrl-D to stop entering numbers.
按 Ctrl-D 停止输入数字。
回答by vardhan
Here's my 2 cents.
这是我的 2 美分。
#!/bin/sh
read -p "Enter server names separated by 'space' : " input
for i in ${input[@]}
do
echo ""
echo "User entered value :"$i # or do whatever with individual element of the array
echo ""
done
