C# 如何从 Asp.net 2.0 中的代码背后的按钮单击弹出警报？
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时间：2020-08-06 21:50:48 来源:igfitidea点击:
How to popup a Alert on Button Click from code behind in Asp.net 2.0?
提问by Avi
I tried this code but is not working ..
我试过这段代码，但不工作..
protected void btnAbc_Click(object sender, EventArgs e)
{
string script = "<script language='javascript'>alert('abc');</script>";"
ClientScript.RegisterClientScriptBlock(this.GetType(), "Alert", script,true);
}
Pls advice.
请建议。
采纳答案by Guffa
You have double script tags. Add the script tags yourself:
你有双脚本标签。自己添加脚本标签：
protected void btnAbct_Click(object sender, EventArgs e) {
string script = "<script type=\"text/javascript\">alert('abc');</script>";
ClientScript.RegisterClientScriptBlock(this.GetType(), "Alert", script);
}
Or let the method add it:
或者让方法添加它：
protected void btnAbct_Click(object sender, EventArgs e) {
string script = "alert('abc');";
ClientScript.RegisterClientScriptBlock(this.GetType(), "Alert", script, true);
}
Not both.
不是都。
Also consider if the RegisterStartupScriptmethod is a better fit for what you want to do.
还要考虑该RegisterStartupScript方法是否更适合您想要做的事情。
回答by ACP
ScriptManager.RegisterStartupScript(this, this.GetType(), "alerts", "javascript:alert('hai')", true);
or
或者
string script = "alert(\"Hello!\");";
ScriptManager.RegisterStartupScript(this, this.GetType(), "ServerControlScript", script, true);
