使用 HTML data-attribute 设置 CSS background-image url

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/15734546/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-29 22:16:45  来源:igfitidea点击:

Using HTML data-attribute to set CSS background-image url

cssbackground-imagecustom-data-attribute

提问by StephenKelzer

I plan on building a custom photo gallery for a friend and I know exactly how I am going to be producing the HTML, however I am running into a small issue with the CSS.
(I would prefer to not have the page styling rely on jQuery if possible)

我计划为朋友构建一个自定义照片库,我确切地知道我将如何生成 HTML,但是我遇到了 CSS 的一个小问题。
(如果可能的话,我希望页面样式不依赖于 jQuery)



我的问题是:


Data-AttributeData-Attribute在 HTML


Background-imageBackground-image中的 CSS

我正在为我的 html 缩略图使用这种格式:


<div class="thumb" data-image-src="images/img.jpg"></div><div class="thumb" data-image-src="images/img.jpg"></div>





and I assume the CSS should look something like this:

我假设 CSS 应该是这样的:

.thumb {
    width:150px;
    height:150px;
    background-position:center center;
    overflow:hidden;
    border:1px solid black;

    background-image: attr(data-image-src);/*This is the question piece*/
}



我的目标是data-image-srcdata-image-srcdiv.thumbdiv.thumb我的 HTML 文件中获取 ,并将其用于我的 CSS 文件中的每个div.thumbdiv.thumb(s)background-imagebackground-image源。

Here is a Codepen Pen in order to get a dynamic example of what I am looking for:
http://codepen.io/thestevekelzer/pen/rEDJv

这是一个 Codepen Pen 以获得我正在寻找的动态示例:http:
//codepen.io/thestevekelzer/pen/rEDJv

采纳答案by StephenKelzer

You will eventually be able to use

您最终将能够使用

background-image: attr(data-image-src url);

but that is not implemented anywhere yet to my knowledge. In the above, urlis an optional "type-or-unit" parameter to attr(). See https://drafts.csswg.org/css-values/#attr-notation.

但据我所知,这还没有在任何地方实施。在上面,url是一个可选的“类型或单位”参数attr()。请参阅https://drafts.c​​sswg.org/css-values/#attr-notation

回答by Kevin Johne

It is not best practise to mix up content with style, but a solution could be

将内容与风格混为一谈并不是最佳做法,但解决方案可能是

<div class="thumb" style="background-image: url('images/img.jpg')"></div>

回答by Bruce Brotherton

If you wanted to keep it with just HTML and CSS you can use CSS Variables. Keep in mind, css variables aren't supported in IE.

如果您只想使用 HTML 和 CSS 保留它,您可以使用 CSS 变量。请记住,IE 不支持 css 变量

<div class="thumb" style="--background: url('images/img.jpg')"></div> 
.thumb {
    background-image: var(--background);
}

Codepen: https://codepen.io/bruce13/pen/bJdoZW

代码笔:https://codepen.io/bruce13/pen/bJdoZW

回答by Jonathan

You will need a little JavaScript for that:

为此,您需要一点 JavaScript:

var list = document.getElementsByClassName('thumb');

for (var i = 0; i < list.length; i++) {
  var src = list[i].getAttribute('data-image-src');
  list[i].style.backgroundImage="url('" + src + "')";
}

Wrap that in <script>tags at the bottom just before the </body>tag or wrap in a function that you call once the page loaded.

将其包装在<script>标签之前底部的</body>标签中,或者包装在页面加载后调用的函数中。

回答by CodeFinity

How about using some Sass? Here's what I did to achieve something like this (although note that you have to create a Sass list for each of the data-attributes).

使用一些 Sass 怎么样?这是我为实现这样的目标所做的工作(尽管请注意,您必须为每个数据属性创建一个 Sass 列表)。

/*
  Iterate over list and use "data-social" to put in the appropriate background-image.
*/
$social: "fb", "twitter", "youtube";

@each $i in $social {
  [data-social="#{$i}"] {
    background: url('#{$image-path}/icons/#{$i}.svg') no-repeat 0 0;
    background-size: cover; // Only seems to work if placed below background property
  }
}

Essentially, you list all of your data attribute values. Then use Sass @each to iterate through and select all the data-attributes in the HTML. Then, bring in the iterator variable and have it match up to a filename.

本质上,您列出了所有数据属性值。然后使用 Sass @each 迭代并选择 HTML 中的所有数据属性。然后,引入迭代器变量并使其与文件名匹配。

Anyway, as I said, you have to list all of the values, then make sure that your filenames incorporate the values in your list.

无论如何,正如我所说,您必须列出所有值,然后确保您的文件名包含列表中的值。

回答by Fritz

HTML

HTML

<div class="thumb" data-image-src="img/image.png">

jQuery

jQuery

$( ".thumb" ).each(function() {
  var attr = $(this).attr('data-image-src');

  if (typeof attr !== typeof undefined && attr !== false) {
      $(this).css('background', 'url('+attr+')');
  }

});

Demo on JSFiddle

JSFiddle 上演示

You could do this also with JavaScript.

你也可以用 JavaScript 做到这一点。

回答by Nevil Saul Blemuss

HTML CODE

代码

<div id="borderLoader"  data-height="230px" data-color="lightgrey" data- 
width="230px" data-image="https://fiverr- res.cloudinary.com/t_profile_thumb,q_auto,f_auto/attachments/profile/photo/a54f24b2ab6f377ea269863cbf556c12-619447411516923848661/913d6cc9-3d3c-4884-ac6e-4c2d58ee4d6a.jpg">

</div>

JS CODE

代码

var dataValue, dataSet,key;
dataValue = document.getElementById('borderLoader');
//data set contains all the dataset that you are to style the shape;
dataSet ={ 
   "height":dataValue.dataset.height,
   "width":dataValue.dataset.width,
   "color":dataValue.dataset.color,
   "imageBg":dataValue.dataset.image
};

dataValue.style.height = dataSet.height;
dataValue.style.width = dataSet.width;
dataValue.style.background = "#f3f3f3 url("+dataSet.imageBg+") no-repeat 
center";

回答by lupoll88

For those who want a dumb down answer like me

对于那些像我这样想要一个愚蠢的答案的人

Something like how to steps as 1, 2, 3

像如何步骤 1、2、3 之类的东西

Here it is what I did

这就是我所做的

First create the HTML markup

首先创建 HTML 标记

<div class="thumb" data-image-src="images/img.jpg"></div>

Then before your ending body tag, add this script

然后在结束正文标记之前,添加此脚本

I included the ending body on the code below as an example

我在下面的代码中包含了结尾正文作为示例

So becareful when you copy

所以复制的时候要小心

<script>
var list = document.getElementsByClassName('thumb');

for (var i = 0; i < list.length; i++) {
  var src = list[i].getAttribute('data-image-src');
  list[i].style.backgroundImage="url('" + src + "')";
}
</script>

</body>