C# 字母数字密码的正则表达式，至少包含 1 个数字和字符
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Regex for alphanumeric password, with at least 1 number and character
提问by mrblah
Need help with a regex for alphanumeric password, with at least 1 number and character, and the length must be between 8-20 characters.
需要关于字母数字密码的正则表达式的帮助，至少有 1 个数字和字符，长度必须在 8-20 个字符之间。
I have this but doesn't seem to be working (it doesn't have length requirements either):
我有这个，但似乎没有用（它也没有长度要求）：
^[A-Za-z0-9]*[A-Za-z][A-Za-z0-9]*$
回答by cwap
^(?=.{8,20}$)(?=.*[0-9])(?=.*[a-zA-Z]).*
? :)
? :)
回答by Sanjay Sheth
Wouldn't it be better to do this validation with some simple string functions instead of trying to shoehorn a difficult to validate regex into doing this?
用一些简单的字符串函数来做这个验证，而不是试图用一个难以验证的正则表达式来做这个，不是更好吗？
回答by Adam Robinson
If you take a look at this MSDN link, it gives an example of a password validation RegEx expression, and (more specifically) how to use it in ASP.NET.
如果您查看此MSDN 链接，它提供了密码验证 RegEx 表达式的示例，以及（更具体地说）如何在 ASP.NET 中使用它。
For what you're looking to accomplish, this should work:
对于您要完成的工作，这应该有效：
(?!^[0-9]*$)(?!^[a-zA-Z]*$)^([a-zA-Z0-9]{8,20})$
This requires at least one digit, at least one alphabetic character, no special characters, and from 8-20 characters in length.
这需要至少一位数字，至少一个字母字符，没有特殊字符，并且长度为 8-20 个字符。
回答by John Fisher
Something like this will be closer to your needs. (I didn't test it, though.)
这样的事情将更接近您的需求。（不过，我没有测试它。）
Regex test = new Regex("^(?:(?<ch>[A-Za-z])|(?<num>[9-0])){8,20}$");
Match m = test.Match(input);
if (m.Success && m.Groups["ch"].Captures.Count > 1 && m.Groups["num"].Captures.Count > 1)
{
// It's a good password.
}
回答by S Pangborn
Why not just use a handful of simple functions to check?
为什么不使用一些简单的函数来检查呢？
checkPasswordLength( String password);
checkPasswordNumber( String password);
Maybe a few more to check for occurrences of the same character repeatedly and consecutively.
也许还有几个来重复和连续检查相同字符的出现。
回答by Raj kumar pandey
This code is for javascript
此代码用于 javascript
// *********** ALPHA-Numeric check ***************************
function checkAlphaNumeric(val)
{
var mystring=new String(val)
if(mystring.search(/[0-9]+/)==-1) // Check at-leat one number
{
return false;
}
if(mystring.search(/[A-Z]+/)==-1 && mystring.search(/[a-z]+/)==-1) // Check at-leat one character
{
return false;
}
}
