C# 在WPF中使用Image控件显示System.Drawing.Bitmap
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原文地址: http://stackoverflow.com/questions/1118496/
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Using Image control in WPF to display System.Drawing.Bitmap
提问by Prashant Cholachagudda
How do I assign an in-memory Bitmapobject to an Imagecontrol in WPF ?
如何将内存Bitmap对象分配给ImageWPF 中的控件？
采纳答案by Lars Truijens
You can use the Source property of the image. Try this code...
您可以使用图像的 Source 属性。试试这个代码...
ImageSource imageSource = new BitmapImage(new Uri("C:\FileName.gif"));
image1.Source = imageSource;
回答by Lars Truijens
According to http://khason.net/blog/how-to-use-systemdrawingbitmap-hbitmap-in-wpf/
根据http://khason.net/blog/how-to-use-systemdrawingbitmap-hbitmap-in-wpf/
[DllImport("gdi32")]
static extern int DeleteObject(IntPtr o);
public static BitmapSource loadBitmap(System.Drawing.Bitmap source)
{
IntPtr ip = source.GetHbitmap();
BitmapSource bs = null;
try
{
bs = System.Windows.Interop.Imaging.CreateBitmapSourceFromHBitmap(ip,
IntPtr.Zero, Int32Rect.Empty,
System.Windows.Media.Imaging.BitmapSizeOptions.FromEmptyOptions());
}
finally
{
DeleteObject(ip);
}
return bs;
}
It gets System.Drawing.Bitmap (from WindowsBased) and converts it into BitmapSource, which can be actually used as image source for your Image control in WPF.
它获取 System.Drawing.Bitmap（来自 WindowsBased）并将其转换为 BitmapSource，它实际上可以用作 WPF 中 Image 控件的图像源。
image1.Source = YourUtilClass.loadBitmap(SomeBitmap);
回答by Badiboy
It's easy for disk file, but harder for Bitmap in memory.
磁盘文件很容易，但内存中的位图更难。
System.Drawing.Bitmap bmp;
Image image;
...
MemoryStream ms = new MemoryStream();
bmp.Save(ms, System.Drawing.Imaging.ImageFormat.Png);
ms.Position = 0;
BitmapImage bi = new BitmapImage();
bi.BeginInit();
bi.StreamSource = ms;
bi.EndInit();
image.Source = bi;
回答by Mr47
I wrote a program with wpfand used Database for showing images and this is my code:
我编写了一个程序，wpf并使用数据库来显示图像，这是我的代码：
SqlConnection con = new SqlConnection(@"Data Source=HITMAN-PC\MYSQL;
Initial Catalog=Payam;
Integrated Security=True");
SqlDataAdapter da = new SqlDataAdapter("select * from news", con);
DataTable dt = new DataTable();
da.Fill(dt);
string adress = dt.Rows[i]["ImgLink"].ToString();
ImageSource imgsr = new BitmapImage(new Uri(adress));
PnlImg.Source = imgsr;
