在 C# 中替换字符串中的所有特殊字符
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Replace all Special Characters in a string IN C#
提问by Deepu
I would like to find all special characters in a string and replace with a Hyphen (-)
我想在字符串中找到所有特殊字符并用连字符 ( -)替换
I am using the below code
我正在使用下面的代码
string content = "foo,bar,(regular expression replace) 123";
string pattern = "[^a-zA-Z]"; //regex pattern
string result = System.Text.RegularExpressions.Regex.Replace(content,pattern, "-");
OutPut
输出
foo-bar--regular-expression-replace----
foo-bar--regular-expression-replace----
I am getting multiple occurrence of hyphen (---) in the out put.
我在输出中多次出现连字符 (---)。
I would like to get some thing like this
我想得到这样的东西
foo-bar-regular-expression-replace
foo-bar-regular-expression-replace
How do I achieve this
我如何实现这一目标
Any help would be appreciated
任何帮助，将不胜感激
Thanks Deepu
谢谢迪普
回答by Marc Gravell
Try the pattern: "[^a-zA-Z]+"- i.e. replace one-or-more non-alpha (you might allow numeric, though?).
尝试以下模式："[^a-zA-Z]+"- 即替换一个或多个非 alpha（不过，您可能允许使用数字？）。
回答by snarf
Wouldn't this work?
这行不通？
string pattern = "[^a-zA-Z]+";
回答by Richard
why not just do this:
为什么不这样做：
public static string ToSlug(this string text)
{
StringBuilder sb = new StringBuilder();
var lastWasInvalid = false;
foreach (char c in text)
{
if (char.IsLetterOrDigit(c))
{
sb.Append(c);
lastWasInvalid = false;
}
else
{
if (!lastWasInvalid)
sb.Append("-");
lastWasInvalid = true;
}
}
return sb.ToString().ToLowerInvariant().Trim();
}
