C# 在圆的边缘找到坐标
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Finding the coordinates on the edge of a circle
提问by Ian Vink
Using C#:
使用 C#：
How do I get the (x, y) coordinates on the edge of a circle for any given degree, if I have the center coordinates and the radius?
如果我有中心坐标和半径，如何获得任何给定度数的圆边缘上的 (x, y) 坐标？
There is probably SIN, TAN, COSIN and other grade ten math involved... :)
可能涉及到 SIN、TAN、COSIN 和其他十年级数学...... :)
采纳答案by David M
This has nothing to do with C#. There is just some elementary mathematics involved.
这与 C# 无关。只涉及一些初等数学。
x = x0 + r * cos(theta)
y = y0 + r * sin(theta)
theta is in radians, x0 and y0 are the coordinates of the centre, r is the radius, and the angle is measured anticlockwise from the x-axis. But if you want it in C#, and your angle is in degrees:
theta 以弧度为单位，x0 和 y0 是中心坐标，r 是半径，角度是从 x 轴逆时针测量的。但是如果你想在 C# 中使用它，并且你的角度是度数：
double x = x0 + r * Math.Cos(theta * Math.PI / 180);
double y = y0 + r * Math.Sin(theta * Math.PI / 180);
回答by Daniel Vassallo
For a circle with origin (j, k), radius r, and angle tin radians:
对于原点(j, k)、半径r和角度t以弧度表示的圆：
x(t) = r * cos(t) + j
y(t) = r * sin(t) + k
回答by Alastair Pitts
using Pythagoras Theorem (where x1,y1 is the edge point):
使用毕达哥拉斯定理（其中 x1,y1 是边缘点）：
x1 = x + rcos(theta)
y1 = y + rsin(theta)
x1 = x + r cos(theta)
y1 = y + rsin(theta)
in C#, this would look like:
在 C# 中，这看起来像：
x1 = x + radius * Math.Cos(angle * (Math.PI / 180));
y1 = y + radius * Math.Sin(angle * (Math.PI / 180));
where all variables are doublesand angleis in degrees
其中所有的变量都doubles和angle为度
