打开多个文件(OpenFileDialog,C#)
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Opening multiple files (OpenFileDialog, C#)
提问by jay_t55
I'm trying to open multiple files at once with the OpenFileDialog
, using FileNames
instead of FileName
. But I cannot see any examples anywhere on how to accomplish this, not even on MSDN. As far as I can tell - there's no documentation on it either. Has anybody done this before?
我正在尝试OpenFileDialog
使用 ,FileNames
代替FileName
.同时打开多个文件。但是我在任何地方都看不到任何关于如何实现这一点的示例,甚至在 MSDN 上也看不到。据我所知 - 也没有关于它的文档。以前有人这样做过吗?
采纳答案by RRUZ
You must set the OpenFileDialog.Multiselect
Property value to true, and then access the OpenFileDialog.FileNames
property.
您必须将OpenFileDialog.Multiselect
Property 值设置 为 true,然后才能访问该OpenFileDialog.FileNames
属性。
Check this sample
检查这个样本
private void Form1_Load(object sender, EventArgs e)
{
InitializeOpenFileDialog();
}
private void InitializeOpenFileDialog()
{
// Set the file dialog to filter for graphics files.
this.openFileDialog1.Filter =
"Images (*.BMP;*.JPG;*.GIF)|*.BMP;*.JPG;*.GIF|" +
"All files (*.*)|*.*";
// Allow the user to select multiple images.
this.openFileDialog1.Multiselect = true;
// ^ ^ ^ ^ ^ ^ ^
this.openFileDialog1.Title = "My Image Browser";
}
private void selectFilesButton_Click(object sender, EventArgs e)
{
DialogResult dr = this.openFileDialog1.ShowDialog();
if (dr == System.Windows.Forms.DialogResult.OK)
{
// Read the files
foreach (String file in openFileDialog1.FileNames)
{
// Create a PictureBox.
try
{
PictureBox pb = new PictureBox();
Image loadedImage = Image.FromFile(file);
pb.Height = loadedImage.Height;
pb.Width = loadedImage.Width;
pb.Image = loadedImage;
flowLayoutPanel1.Controls.Add(pb);
}
catch (SecurityException ex)
{
// The user lacks appropriate permissions to read files, discover paths, etc.
MessageBox.Show("Security error. Please contact your administrator for details.\n\n" +
"Error message: " + ex.Message + "\n\n" +
"Details (send to Support):\n\n" + ex.StackTrace
);
}
catch (Exception ex)
{
// Could not load the image - probably related to Windows file system permissions.
MessageBox.Show("Cannot display the image: " + file.Substring(file.LastIndexOf('\'))
+ ". You may not have permission to read the file, or " +
"it may be corrupt.\n\nReported error: " + ex.Message);
}
}
}
回答by Matin
You can use this method for text files:
您可以将此方法用于文本文件:
OpenFileDialog open = new OpenFileDialog();
open.Filter = "All Files *.txt | *.txt";
open.Multiselect = true;
open.Title = "Open Text Files";
if (open.ShowDialog() == DialogResult.OK)
{
foreach (String file in open.FileNames)
{
string temp = YourRichTextBox.Text;
YourRichTextBox.LoadFile(file, RichTextBoxStreamType.PlainText);
YourRichTextBox.Text += temp;
}
}