C# 通用 List<T> 作为方法的参数
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Generic List<T> as parameter on method
提问by Jonathan Escobedo
How can I use a List<T>
as a parameter on a method, I try this syntax :
如何使用 aList<T>
作为方法的参数,我尝试使用以下语法:
void Export(List<T> data, params string[] parameters){
}
I got compilation error:
我收到编译错误:
The type or namespace name 'T' could not be found (are you missing a using directive or an assembly reference?)
找不到类型或命名空间名称“T”(您是否缺少 using 指令或程序集引用?)
采纳答案by JaredPar
To take a generic List<T>
vs a bound List<int>
you need to make the method generic as well. This is done by adding a generic parameter to the method much in the way you add it to a type.
要采用泛型List<T>
与界限,List<int>
您还需要使方法通用。这是通过向方法添加泛型参数来完成的,这与将其添加到类型的方式非常相似。
Try the following
尝试以下
void Export<T>(List<T> data, params string[] parameters) {
...
}
回答by Fredrik M?rk
You need to make the method generic as well:
您还需要使该方法通用:
void Export<T>(List<T> data, params string[] parameters){
}
回答by user3418564
public static List<T> pesquisa_lista<T>(string campo, string valor, List<T> lista)
{
return new List<T>();
}