Linux 为什么 STRACE 显示 EAGAIN(资源暂时不可用)
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/17666145/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Why STRACE shows EAGAIN (Resource temporarily unavailable)
提问by Avinash
Following is the sequence I am getting
以下是我得到的序列
socket(PF_INET, SOCK_STREAM, IPPROTO_IP) = 7
setsockopt(7, SOL_TCP, TCP_NODELAY, [1], 4) = 0
setsockopt(7, SOL_SOCKET, SO_SNDBUF, [32120], 4) = 0
getsockopt(7, SOL_SOCKET, SO_SNDBUF, [30064835312], [4]) = 0
setsockopt(7, SOL_SOCKET, SO_SNDBUF, [64240], 4) = 0
getsockopt(7, SOL_SOCKET, SO_SNDBUF, [30064899552], [4]) = 0
stat("/etc/localtime", {st_dev=makedev(8, 1), st_ino=229001, st_mode=S_IFREG|0644, st_nlink=1, st_uid=0, st_gid=0, st_blksize=4096, st_blocks=8, st_size=265, st_atime=2013/07/15-06:30:03, st_mtime=2012/06/25-23:46:43, st_ctime=2012/06/25-23:46:43}) = 0
write(1, "[info 2013/07/16 05:53:24.622210"..., 114) = 114
setsockopt(7, SOL_SOCKET, SO_RCVBUF, [32120], 4) = 0
getsockopt(7, SOL_SOCKET, SO_RCVBUF, [30064835312], [4]) = 0
setsockopt(7, SOL_SOCKET, SO_RCVBUF, [64240], 4) = 0
getsockopt(7, SOL_SOCKET, SO_RCVBUF, [30064899552], [4]) = 0
fcntl(7, F_GETFL) = 0x2 (flags O_RDWR)
fcntl(7, F_SETFL, O_RDWR|O_NONBLOCK) = 0
rt_sigaction(SIGPIPE, {SIG_IGN, [PIPE], SA_RESTORER|SA_RESTART, 0x33b3632920}, {SIG_DFL, [], 0}, 8) = 0
fcntl(7, F_GETFL) = 0x802 (flags O_RDWR|O_NONBLOCK)
fcntl(7, F_SETFL, O_RDWR|O_NONBLOCK) = 0
connect(7, {sa_family=AF_INET, sin_port=htons(50505), sin_addr=inet_addr("1.2.3.4")}, 16) = -1 EINPROGRESS (Operation now in progress)
poll([{fd=7, events=POLLIN|POLLOUT}], 1, 59000) = 1 ([{fd=7, revents=POLLOUT}])
fcntl(7, F_GETFL) = 0x802 (flags O_RDWR|O_NONBLOCK)
fcntl(7, F_SETFL, O_RDWR) = 0
getsockname(7, {sa_family=AF_INET, sin_port=htons(33220), sin_addr=inet_addr("10.112.204.215")}, [16]) = 0
fcntl(7, F_GETFL) = 0x2 (flags O_RDWR)
fcntl(7, F_GETFL) = 0x2 (flags O_RDWR)
fcntl(7, F_SETFL, O_RDWR|O_NONBLOCK) = 0
write(7, "d;7707&W\\np47##代码####代码####代码##W##代码##\rpnq-gst-"..., 103) = 103
fcntl(7, F_GETFL) = 0x802 (flags O_RDWR|O_NONBLOCK)
fcntl(7, F_SETFL, O_RDWR) = 0
fcntl(7, F_GETFL) = 0x2 (flags O_RDWR)
fcntl(7, F_GETFL) = 0x2 (flags O_RDWR)
fcntl(7, F_SETFL, O_RDWR|O_NONBLOCK) = 0
read(7, 0x9d9f90, 1) = -1 EAGAIN (Resource temporarily unavailable)
Why this read is getting called, I assume that poll
should wake up only when there is data to read
为什么这个读取被调用,我认为poll
只有在有数据要读取时才应该唤醒
采纳答案by Barmar
poll
woke up with revents = POLLOUT
, which means that the socket is ready to write, not ready to read. The code is apparently not checking this flag, and trying to read anyway.
poll
用 唤醒revents = POLLOUT
,这意味着套接字已准备好写入,未准备好读取。代码显然没有检查这个标志,并试图阅读。
This might be intentional. Even though poll
didn't say the socket is ready to read, it might have become ready while it was writing. So it calls ready just in case something has shown up. If not, it will go back into poll
to wait again. This allows it to process incoming data more quickly, since it can get it in one call rather than two.
这可能是故意的。即使poll
没有说套接字已准备好读取,它也可能在写入时准备就绪。所以它会调用 ready 以防万一出现了问题。如果没有,它会重新进入poll
等待。这使它能够更快地处理传入的数据,因为它可以通过一次调用而不是两次调用来获取它。