带有“任何泛型类型”定义的 C# 泛型“where 约束”？
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C# generic "where constraint" with "any generic type" definition?
提问by Nenad
Let me give example:
我举个例子：
I have some generic class/interface definition:
interface IGenericCar< T > {...}I have another class/interface that I want to relate with class above, for example:
interface IGarrage< TCar > : where TCar: IGenericCar< (**any type here**) > {...}
我有一些通用的类/接口定义：
interface IGenericCar< T > {...}我有另一个类/接口，我想与上面的类相关联，例如：
interface IGarrage< TCar > : where TCar: IGenericCar< (**any type here**) > {...}
Basically, I want my generic IGarrage to be dependent on IGenericCar, regardless if it's IGenericCar<int>or IGenericCar<System.Color>, because I don't have any dependency to that type.
基本上，我希望我的通用 IGarrage 依赖于IGenericCar，无论它是IGenericCar<int>或IGenericCar<System.Color>，因为我对该类型没有任何依赖性。
采纳答案by JaredPar
There are typically 2 ways to achieve this.
通常有两种方法可以实现这一点。
Option1: Add another parameter to IGarragerepresenting the Twhich should be passed into the IGenericCar<T>constraint:
Option1：添加另一个参数来IGarrage表示T应该传递给IGenericCar<T>约束的参数：
interface IGarrage<TCar,TOther> where TCar : IGenericCar<TOther> { ... }
Option2: Define a base interface for IGenericCar<T>which is not generic and constrain against that interface
选项2：定义一个IGenericCar<T>非通用的基本接口并限制该接口
interface IGenericCar { ... }
interface IGenericCar<T> : IGenericCar { ... }
interface IGarrage<TCar> where TCar : IGenericCar { ... }
回答by snarf
Would it make any sense to do something like:
这样做是否有意义：
interface IGenericCar< T > {...}
interface IGarrage< TCar, TCarType >
where TCar: IGenericCar< TCarType > {...}
