linux shell 是否支持列表数据结构？
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does linux shell support list data structure?
提问by hugemeow
this question is not the same as Does the shell support sets?
这个问题和Does the shell support sets不一样？
i know lots of script language support list structure, such as python, python, ruby, and javascript, so what about linux shell?
我知道很多脚本语言支持列表结构，比如python、python、ruby和javascript，那么linux shell呢？
does shell support such syntax?
shell 支持这样的语法吗？
for i in list:
do
print i
done
i would first to initialize a list, for example:
我会首先初始化一个列表，例如：
ListName = [ item1, item2, ..., itemn ]
then iterate over it
然后迭代它
is that possible when programming shell scripts?
编程shell脚本时可能吗？
采纳答案by chepner
It supports lists, but not as a separate data structure (ignoring arrays for the moment).
它支持列表，但不作为单独的数据结构（暂时忽略数组）。
The forloop iterates over a list (in the generic sense) of white-space separated values, regardless of how that list is created, whether literally:
在for白色空间在列表循环迭代（一般意义上的）分隔值，不管如何被创建的列表，无论是从字面上：
for i in 1 2 3; do
echo "$i"
done
or via parameter expansion:
或通过参数扩展：
listVar="1 2 3"
for i in $listVar; do
echo "$i"
done
or command substitution:
或命令替换：
for i in $(echo 1; echo 2; echo 3); do
echo "$i"
done
An array is just a special parameter which can contain a more structured list of value, where each element can itself contain whitespace. Compare the difference:
数组只是一个特殊的参数，它可以包含一个更结构化的值列表，其中每个元素本身可以包含空格。比较差异：
array=("item 1" "item 2" "item 3")
for i in "${array[@]}"; do # The quotes are necessary here
echo "$i"
done
list='"item 1" "item 2" "item 3"'
for i in $list; do
echo $i
done
for i in "$list"; do
echo $i
done
for i in ${array[@]}; do
echo $i
done
回答by DonCallisto
For make a list, simply do that
要列出清单，只需这样做
colors=(red orange white "light gray")
Technically is an array, but - of course - it has all list features.
Even python list are implemented with array
从技术上讲是一个数组，但是 - 当然 - 它具有所有列表功能。
甚至python列表也是用数组实现的
