使用 execl 运行 Linux 命令
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Using execl to run a Linux command
提问by femchi
I need to list all files in the current directory which have a permission of 644 by writing a C language program.
I can not use system()and have to use execl()in order to use system calls.
我需要通过编写一个C语言程序列出当前目录中所有权限为644的文件。我不能使用system()并且必须使用execl()才能使用系统调用。
This a line that I used in my code:
这是我在代码中使用的一行：
execl("/usr/bin/find", "find . -maxdepth 1 -perm 644", (char *)NULL);
The problem is that the code is searching the whole disk instead of the current directory. Would you help me to fix it please?
问题是代码正在搜索整个磁盘而不是当前目录。请你帮我修好吗？
...
case 4:
int status;
switch (fork()){
case -1: quit ("fork",1);
case 0:
execl("/usr/bin/find","find","." ,"-maxdepth" ,"1","-perm", "644",(char *)NULL) ;
exit (200);
default:
wait(&status);
exit(0);
}
}
采纳答案by Jonathan Leffler
Separate the arguments:
分隔参数：
execl("/usr/bin/find", "find", ".", "-maxdepth", "1", "-perm", "644", (char *)NULL);
Your invocation was equivalent to invoking the findprogram with no arguments (and a very funny argv[0]).
您的调用相当于调用find没有参数的程序（并且非常有趣argv[0]）。
回答by alinsoar
execl("/usr/bin/find","/usr/bin/find", ".", "-maxdepth", "1", "-perm", "0644",(char *)NULL);
回答by mvp
For your particular task, using file tree walk(ftw) is more appropriate.
对于您的特定任务，使用文件树遍历( ftw) 更合适。
ftw is just a library, so you don't need to spawn external process to get job done. Also, it is much easier to parse results.
ftw 只是一个库，因此您无需生成外部进程即可完成工作。此外，解析结果要容易得多。
