Linux 通过 fork() 创建子进程 shell 脚本中的父进程
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create a child process by fork() a parent process in shell script
提问by Sam
It seems some answers on the site but those seem not to resolve my question.
网站上似乎有一些答案，但那些似乎无法解决我的问题。
Say,
说，
#/bin/sh
fpfunction(){
n=1
while (($n<20))
do
echo "Hello World-- $n times"
sleep 2
echo "Hello World2-- $n times"
n=$(( n+1 ))
done
}
fork(){
count=0
while (($count<=10))
do
fpfunction &
count=$(( count+1 ))
done
}
fork
I am expecting to "fork" this parent process to the number of 10 child processes.
我期待将这个父进程“分叉”到 10 个子进程的数量。
The way I check that those child processes are actually created is to type "ps -l" command.
我检查这些子进程是否实际创建的方法是键入“ps -l”命令。
I am a newbie to the shell world and please let me know how to archive this.
我是 shell 世界的新手，请让我知道如何存档。
Thanks in advance.
提前致谢。
采纳答案by Ignacio Vazquez-Abrams
The ampersand (&) after a command will run it in a forked subshell.
&命令后面的与号( ) 将在分叉的子 shell 中运行它。
fpfunction &
