Linux bash：xargs 传递变量
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bash: xargs passing variable
提问by arminb
How can a global script variable be passed to the command of xargs? I tried it this way:
如何将全局脚本变量传递给 xargs 的命令？我是这样试的：
TEST=hallo2
echo "hallo" | xargs sh -c 'echo passed= test=$TEST' sh
Output:
输出：
passed=hallo test=
I know I could use the {}token but I need to do it this way!
我知道我可以使用{}令牌，但我需要这样做！
I'm using bash.
我正在使用bash.
采纳答案by Ander2
Take variable $TESTout from the quotes:
$TEST从引号中取出变量：
TEST=hallo2
echo "hallo" | xargs sh -c 'echo passed= test='$TEST sh
回答by Carlos Campderrós
Added as an answer as@chepner suggested.
作为@chepner 建议的答案添加。
exportthe variable TEST:
export变量TEST：
export TEST=hallo2
echo "hallo" | xargs sh -c 'echo passed= test="$TEST"' sh
回答by Ole Tange
With GNU Parallel you can avoid some of the quoting:
使用 GNU Parallel，您可以避免一些引用：
TEST=hallo2
echo "hallo" | parallel echo passed={} test=$TEST
GNU Parallel exists as package for most distributions and it is recommended to use the normal package manager for installation. But if there is no package for your system, it still takes literally 10 seconds to install GNU Parallel.
GNU Parallel 作为大多数发行版的包存在，建议使用普通的包管理器进行安装。但是如果你的系统没有安装包，安装 GNU Parallel 仍然需要 10 秒钟。
Watch the intro videos to learn more: https://www.youtube.com/playlist?list=PL284C9FF2488BC6D1
观看介绍视频以了解更多信息：https: //www.youtube.com/playlist?list=PL284C9FF2488BC6D1
