如何通过命令行识别特定的 Linux 风格？
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How do I identify the particular Linux flavor via command line?
提问by mcandre
I'd like to be able to detect which particular Linux flavor is installed on a computer, e.g. Ubuntu vs Fedora, via a command line command.
我希望能够通过命令行命令检测计算机上安装了哪种特定的 Linux 风格，例如 Ubuntu 与 Fedora。
Some people recommend uname -a, but that only reports the kernel version.
有人推荐uname -a，但那只报告内核版本。
采纳答案by ramit girdhar
Try the below command.... It worked for me...
试试下面的命令......它对我有用......
cat /proc/version
猫/过程/版本
Once you know that you are running Red Hat for example, you can get to the point with:
例如，一旦您知道您正在运行 Red Hat，您可以通过以下方式进入正题：
cat /etc/redhat-release
cat /etc/redhat-release
Or on Debian:
或者在 Debian 上：
cat /etc/debian_version
cat /etc/debian_version
or in general :
或者一般来说：
cat /etc/*-release
cat /etc/*-release
Also you could use the following command
您也可以使用以下命令
cat /etc/issue
猫 /etc/issue
回答by Bhanu Kaushik
I hope this works echo $(lsb_release -si)
我希望这有效 echo $(lsb_release -si)
回答by Rag Sagar
For displaying details including release and codename of the distro
用于显示详细信息，包括发行版的发行版和代号
lsb_release -a
