C# 如何从字符串中分离字符和数字部分
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原文地址: http://stackoverflow.com/questions/1968049/
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How to separate character and number part from string
提问by Thunder
E.g., I would like to separate:
例如，我想分开：
OS234toOSand234AA4230toAAand4230
OS234到OS和234AA4230到AA和4230
I have used following trivial solution, but I am quite sure that there should be a more efficient and robust solution .
我使用了以下简单的解决方案，但我很确定应该有一个更有效和更强大的解决方案。
private void demo()
{ string cell="ABCD4321";
int a = getIndexofNumber(cell);
string Numberpart = cell.Substring(a, cell.Length - a);
row = Convert.ToInt32(rowpart);
string Stringpart = cell.Substring(0, a);
}
private int getIndexofNumber(string cell)
{
int a = -1, indexofNum = 10000;
a = cell.IndexOf("0"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("1"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("2"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("3"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("4"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("5"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("6"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("7"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("8"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
a = cell.IndexOf("9"); if (a > -1) { if (indexofNum > a) { indexofNum = a; } }
if (indexofNum != 10000)
{ return indexofNum; }
else
{ return 0; }
}
采纳答案by Thunder
I have used bniwredyc's answer to get Improved version of my routine:
我已经使用 bniwredyc 的答案来获得我的例程的改进版本：
private void demo()
{
string cell = "ABCD4321";
int row, a = getIndexofNumber(cell);
string Numberpart = cell.Substring(a, cell.Length - a);
row = Convert.ToInt32(Numberpart);
string Stringpart = cell.Substring(0, a);
}
private int getIndexofNumber(string cell)
{
int indexofNum=-1;
foreach (char c in cell)
{
indexofNum++;
if (Char.IsDigit(c))
{
return indexofNum;
}
}
return indexofNum;
}
回答by this. __curious_geek
Use Linq to do this
使用 Linq 来做到这一点
string str = "OS234";
var digits = from c in str
select c
where Char.IsDigit(c);
var alphas = from c in str
select c
where !Char.IsDigit(c);
回答by x0n
Regular Expressions are best suited for this kind of work:
正则表达式最适合这种工作：
using System.Text.RegularExpressions;
Regex re = new Regex(@"([a-zA-Z]+)(\d+)");
Match result = re.Match(input);
string alphaPart = result.Groups[1].Value;
string numberPart = result.Groups[2].Value;
回答by jason
Everyone and their mother will give you a solution using regex, so here's one that is not:
每个人和他们的母亲都会使用正则表达式为您提供解决方案，所以这里有一个不是：
// s is string of form ([A-Za-z])*([0-9])* ; char added
int index = s.IndexOfAny(new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' });
string chars = s.Substring(0, index);
int num = Int32.Parse(s.Substring(index));
回答by Aaronaught
Are you doing this for sorting purposes? If so, keep in mind that Regex can kill performance for large lists. I frequently use an AlphanumComparerthat's a general solution to this problem (can handle any sequence of letters and numbers in any order). I believe that I adapted it from this page.
你这样做是为了排序吗？如果是这样，请记住 Regex 可能会降低大型列表的性能。我经常使用AlphanumComparerthat 是这个问题的一般解决方案（可以处理任何顺序的字母和数字序列）。我相信我是从这个页面改编的。
Even if you're not sorting on it, using the character-by-character approach (if you have variable lengths) or simple substring/parse (if they're fixed) will be a lot more efficient and easier to test than a Regex.
即使您不对其进行排序，使用逐个字符的方法（如果您有可变长度）或简单的子字符串/解析（如果它们已修复）也将比 Regex 更有效且更易于测试.
回答by bniwredyc
.NET 2.0 compatible, without regex
.NET 2.0 兼容，无正则表达式
public class Result
{
private string _StringPart;
public string StringPart
{
get { return _StringPart; }
}
private int _IntPart;
public int IntPart
{
get { return _IntPart; }
}
public Result(string stringPart, int intPart)
{
_StringPart = stringPart;
_IntPart = intPart;
}
}
class Program
{
public static Result GetResult(string source)
{
string stringPart = String.Empty;
int intPart;
var buffer = new StringBuilder();
foreach (char c in source)
{
if (Char.IsDigit(c))
{
if (stringPart == String.Empty)
{
stringPart = buffer.ToString();
buffer.Remove(0, buffer.Length);
}
}
buffer.Append(c);
}
if (!int.TryParse(buffer.ToString(), out intPart))
{
return null;
}
return new Result(stringPart, intPart);
}
static void Main(string[] args)
{
Result result = GetResult("OS234");
Console.WriteLine("String part: {0} int part: {1}", result.StringPart, result.IntPart);
result = GetResult("AA4230 ");
Console.WriteLine("String part: {0} int part: {1}", result.StringPart, result.IntPart);
result = GetResult("ABCD4321");
Console.WriteLine("String part: {0} int part: {1}", result.StringPart, result.IntPart);
Console.ReadKey();
}
}
回答by Amir Lavaie
use Split to seprate string from sting that use tab \t and space
使用 Split 将字符串与使用制表符 \t 和空格的字符串分开
string s = "sometext\tsometext\tsometext";
string[] split = s.Split('\t');
now you have an array of string that you want too easy
现在你有一个你想要太容易的字符串数组
回答by Jozef Cechovsky
If you want resolve more occurrences of char followed by number or vice versa you can use
如果您想解决更多出现的字符后跟数字，反之亦然，您可以使用
private string SplitCharsAndNums(string text)
{
var sb = new StringBuilder();
for (var i = 0; i < text.Length - 1; i++)
{
if ((char.IsLetter(text[i]) && char.IsDigit(text[i+1])) ||
(char.IsDigit(text[i]) && char.IsLetter(text[i+1])))
{
sb.Append(text[i]);
sb.Append(" ");
}
else
{
sb.Append(text[i]);
}
}
sb.Append(text[text.Length-1]);
return sb.ToString();
}
And then
进而
var text = SplitCharsAndNums("asd1 asas4gr5 6ssfd");
var tokens = text.Split(' ');
回答by aloisdg moving to codidact.com
I really like jason's answer. Lets improve it a bit. We dont need regex here. My solution handle input like "H1N1":
我真的很喜欢杰森的回答。让我们稍微改进一下。我们这里不需要正则表达式。我的解决方案处理像“H1N1”这样的输入：
public static IEnumerable<string> SplitAlpha(string input)
{
var words = new List<string> { string.Empty };
for (var i = 0; i < input.Length; i++)
{
words[words.Count-1] += input[i];
if (i + 1 < input.Length && char.IsLetter(input[i]) != char.IsLetter(input[i + 1]))
{
words.Add(string.Empty);
}
}
return words;
}
This solution is linear O(n).
这个解是线性的 O(n)。
ouput
输出
"H1N1" -> ["H", "1", "N", "1"]
"H" -> ["H"]
"GH1N12" -> ["GH", "1", "N", "12"]
"OS234" -> ["OS", "234"]
Same solution with a StringBuilder
与一个相同的解决方案 StringBuilder
public static IEnumerable<string> SplitAlpha(string input)
{
var words = new List<StringBuilder>{new StringBuilder()};
for (var i = 0; i < input.Length; i++)
{
words[words.Count - 1].Append(input[i]);
if (i + 1 < input.Length && char.IsLetter(input[i]) != char.IsLetter(input[i + 1]))
{
words.Add(new StringBuilder());
}
}
return words.Select(x => x.ToString());
}
回答by Karshanguna R
Just use the substringfunction and set position inside the bracket.
只需使用该substring功能并在支架内设置位置即可。
String id = "DON123";
System.out.println("Id nubmer is : "+id.substring(3,6));
Answer:
回答：
Id number is: 123
