Linux 使用 $(basename $(notdir $@)) 理解 Makefile
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Understanding a Makefile with $(basename $(notdir $@))
提问by
I am trying to understand a Makefile, but I don't understand the recipe line with the comment.
我试图理解 Makefile，但我不理解注释中的配方行。
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sample.a:
cd ../$(basename $(notdir $@)) && make ##i don't understand this
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I'm still a newbie at this. Can you give me a very simple explanation about:
我在这方面还是个新手。你能给我一个非常简单的解释：
$(basename $(notdir $@))
$(basename $(notdir $@))
采纳答案by lurker
If you break it down:
如果你分解它：
$(notdir $@)takes away the path from the file name leaving just the file name (so /x/y/foo.abecomes foo.a)
$(basename ...)takes away the extension (so foo.abecomes foo)
$(notdir $@)去掉文件名的路径，只留下文件名（所以/x/y/foo.a变成foo.a）
$(basename ...)去掉扩展名（foo.a变成foo）
There's a decent reference here: http://www.gnu.org/software/make/manual/html_node/File-Name-Functions.html
这里有一个不错的参考：http: //www.gnu.org/software/make/manual/html_node/File-Name-Functions.html
